-Ermittlung der Mindestquerkraftbewehrung im gesamten Plattenbalken:
a s w = ρ w , m i n ⋅ b w ⋅ s i n α = 1 , 02 ⋅ 0 , 30 ⋅ 1 = 3 , 06 c m 2 / m _ _ {\displaystyle a_{sw}=\rho _{w,min}\cdot b_{w}\cdot sin\alpha =1,02\cdot 0,30\cdot 1={\underline {\underline {3,06cm^{2}/m}}}}
ρ w , m i n = 1 , 02 {\displaystyle \rho _{w,min}=1,02} aus Tabelle
-Querkraftbemessung im Abstand d von den Auflagern A und C:
V E d = 172 , 67 k N {\displaystyle V_{Ed}=172,67kN} σ c d = 0 {\displaystyle \sigma _{cd}=0} α = 90 {\displaystyle \alpha =90} °
-Druckstrebenneigungswinkel:
c o t θ = 1 , 2 1 − V R d , c c / V E d = 1 , 2 1 − 0 , 1118 / 0 , 17267 = 3 , 40 {\displaystyle cot\theta ={\cfrac {1,2}{1-V_{Rd,cc}/V_{Ed}}}={\cfrac {1,2}{1-0,1118/0,17267}}=3,40} > 3 , 0 _ {\displaystyle >{\underline {3,0}}} maßgebend
- z = 0 , 9 ⋅ d ≤ d − 2 ⋅ c v , l = 0 , 9 ⋅ 54 , 5 = 49 , 05 c m ≤ 54 , 5 − 2 ⋅ 3 , 5 = 47 , 5 c m _ {\displaystyle z=0,9\cdot d\leq d-2\cdot c_{v,l}=0,9\cdot 54,5=49,05cm\leq 54,5-2\cdot 3,5={\underline {47,5cm}}}
- V R d , c c = 0 , 24 ⋅ f c k 1 / 3 ⋅ b w ⋅ z = 0 , 24 ⋅ 35 1 / 3 ⋅ 0 , 3 ⋅ 0 , 475 = 0 , 1118 M N _ {\displaystyle V_{Rd,cc}=0,24\cdot f_{ck}^{1/3}\cdot b_{w}\cdot z=0,24\cdot 35^{1/3}\cdot 0,3\cdot 0,475={\underline {0,1118MN}}}